Write each sum using summation notation12 + 22 + 32 + 42 + ⋯ + 10000^2

Answer:50,00,70,000Step-by-step explanation:The given sequence is Arithmetic Progression. Arithmetic Progression is a sequence in which every two neighbor digits have equal distances. Here first we will find the number of termsFor finding the nth term, we use formula aₙ = a + (n - 1) d where, aₙ = value of nth term a = First term n = number of term d = difference Now, In given sequence: 12, 22, 32, 42, ⋯ , 100002a = 12, d = 10, n = ? and  aₙ= 100002∴ 100002  = 12 + (n - 1) × (10) ⇒ 99990 = 10(n - 1)⇒ n = 10000Now using the formula of Sum of Arithmetic Sequence,Sₙ = n÷2[2a + (n - 1)d]⇒ Sₙ = (10000÷2)[2 × 12 + 9999 × 10]⇒ Sₙ = 5000 [ 24 + 99990]⇒ Sₙ = 5000 × 100014 = 50,00,70,000