MATH SOLVE

3 months ago

Q:
# A toy rocket is launched from a platform 29 feet above the ground at a speed of 79 feet per second. The height of the rocket in feet is given by the polynomial −16t^2 + 79t + 29, where t is the time in seconds. How high will the rocket be after 3 seconds?

Accepted Solution

A:

:)

Height = -16t² + 79t + 29

3 sec means t = 3, we substitute t with 3

H = -16(3)² + 79(3) + 29

= -144 + 237 +29

= 122 feet

Height = -16t² + 79t + 29

3 sec means t = 3, we substitute t with 3

H = -16(3)² + 79(3) + 29

= -144 + 237 +29

= 122 feet